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mntb
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v'=(v-u)/(1-vu/c^2), then dv'=? is it (dv-u)/(1-udv/c^2)?
Derivating a from v (lorentz transform)
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SUMMARY
The discussion centers on the derivation of the Lorentz transformation equation for velocity, specifically the transformation of velocity v to v' using the formula v'=(v-u)/(1-vu/c^2). The user seeks clarification on the differential form, questioning whether dv' can be expressed as (dv-u)/(1-udv/c^2). The conversation emphasizes the importance of proper posting etiquette, directing users to place homework-related inquiries in the designated section of the forum.
PREREQUISITES- Understanding of Lorentz transformations in special relativity
- Familiarity with calculus, particularly differentiation
- Knowledge of the speed of light constant (c)
- Basic principles of velocity addition in physics
- Study the derivation of the Lorentz transformation equations
- Learn about differential calculus applications in physics
- Explore the implications of velocity addition in relativistic contexts
- Review the concept of reference frames in special relativity
Physics students, educators, and anyone interested in the mathematical foundations of special relativity and the Lorentz transformation.
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