Calculating Speed, Acceleration & Force of a 75kg Man Falling 3.10m

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SUMMARY

The discussion focuses on calculating the speed, acceleration, and force experienced by a 75 kg man falling from a height of 3.10 meters. The speed upon impact with the ground is determined to be 7.79487 m/s. To find the constant acceleration during deceleration, users are advised to apply the basic equation of motion: x = v_0t + ½ at². Additionally, the net force and average force exerted by the man's feet on the ground during deceleration are also explored.

PREREQUISITES
  • Understanding of basic physics concepts such as speed, acceleration, and force.
  • Familiarity with the equation of motion: x = v_0t + ½ at².
  • Knowledge of Newton's second law of motion for calculating net force.
  • Basic mathematical skills for solving equations and manipulating variables.
NEXT STEPS
  • Learn how to apply Newton's second law of motion to various scenarios.
  • Explore kinematic equations for different types of motion.
  • Study the concept of impulse and momentum in physics.
  • Investigate the effects of different surfaces on deceleration forces.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of falling objects and the forces involved in impact scenarios.

alafleur1
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1) A 75 kg man falls 3.10 meters to the ground. He moves an additional 0.6 meters as his knees bend when he hits the ground.
a) what is his speed as his speed when his feet touch the ground? - I solved this as 7.79487 m/s
b) What is his acceleration as he slows down if acceleration is assumed to be a constant? How do i get this?
c) What is the net force on the man and what is the average force his feet exert on the ground as he slows?
 
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Hint: use the basic equation of motion:

[tex]x = v_0t + \frac{1}{2} at^2[/tex]

and think of it as two separate problems.
 
Last edited:

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