:Implicit Differentiation Problem - Check my work?:

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Homework Help Overview

The discussion revolves around an implicit differentiation problem involving the equation xcos(y) + ycos(x) = 1. Participants are examining the differentiation process and checking the correctness of the original poster's work.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to differentiate the given equation implicitly and seeks verification of their final expression for dy/dx. Some participants question the steps taken, particularly in relation to the second problem involving the square root of xy.

Discussion Status

Some participants affirm the correctness of the original poster's final answer for dy/dx, while others express difficulty in starting the second problem. There is an indication that further exploration of the second problem is encouraged.

Contextual Notes

Participants note challenges with the initial steps of the second problem, particularly regarding the differentiation of the square root function. The original poster also expresses uncertainty about the placement of their question in the forum.

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:Implicit Differentiation Problem -- Check my work?:

Think I placed this in the wrong forum...

I've worked it -- can someone just check my work?

Problem:

xcosy+ycos=1

My work:

[x (d/x)cosy + cosy (d/dx)x] + [y (d/dx)cosx + cosx (d/dx)y] = (d/dx) 1

-xsiny (dy/dx) + cos y - ysinx + cos x (dy/dx) = 0

-xsiny (dy/dx) + cos y = ysinx - cosy

dy/dx = (ysinx - cosy)/(-xsiny + cos x)


Meanwhile, could someone help me with this one...

squareroot (xy) = 1+(x^2)y
 
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dy/dx = (ysinx - cosy)/(-xsiny + cos x)

this final answer is right.

The second one is probably easier, have a go at it at least and we'll check the answer again?
 
Well, the problem with that one is the idea that I can't even get the first step... the derivative of sqrt (xy)
 
Square the equation.
 

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