Calculating Average Power for Acceleration: 630 kg Car, 0-65 mi/h in 6.0 sec

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SUMMARY

The average power required to accelerate a 630 kg car from 0 to 65 mph in 6.0 seconds can be calculated using the correct formula for kinetic energy, which is KE = (1/2)mv². The change in kinetic energy must be computed after converting the speed from miles per hour to meters per second. The correct conversion yields a final speed of approximately 29.06 m/s, leading to a kinetic energy of 26778.57 J. This value can then be used in the power formula P = W/t to find the average power output.

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What is the average power needed to accelerate a 630 kg car from 0 to 65 mi/h in 6.0 seconds? Assume that all forms of frictional losses can be ignored.

i've calculated change in kinetic energy to be 20475 J using: 1/2mv(final) - 1/2mv(initial). Since, change in kinetic energy is equal to work, i applied it to P = W/t. The answer I am getting is wrong and I've also tried converting mi/h to m/s and the answer is still not right, what am i doing wrong??
 
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it looks like you used 65 mph in your calculation!

You should try to be consistent with your units.
If you're going to have the work done expressed in Joules, then use SI units all the way. Convert the speed to metric first of all.

Oh yes, the formula you used is incorrect, I'm afraid.
The KE is given by (1/2)mv² - not (1/2)mv.
 
To get joules, you're going to have to convert miles/hour to m/s. It's best to do this before you try and calculate Work. What's the final speed of the car in m/s?
 

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