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bmore007
Oct3-05, 09:00 PM
1.05 = (ViSin30)10 * ViCos30+ 1/2(-9.8)(10/ViCos30)^2


help me solve for Vi please

robphy
Oct3-05, 09:42 PM
Can you do some algebra to separate out the factors of Vi in each term on the right-hand side?
You might want to take care in using parenthesis around (ViCos30), especially in the second term on the right-hand side.

bmore007
Oct3-05, 09:47 PM
all the #'s i'm getting are turning out wrong

robphy
Oct3-05, 09:56 PM
Let's go slowly... do algebra first (arithmetic last). It's easier to spot an algebra mistake.

Can you factor "(ViSin30)10 * ViCos30" ?
It may help to forget the numbers and think of this symbolically as (V_i A)B * V_iC. So, can you factor this expression and write it in terms of V_i, A, B, and C?

bmore007
Oct3-05, 10:01 PM
"Can you factor "(ViSin30)10 * ViCos30" ?"


4.33Vi

robphy
Oct3-05, 10:06 PM
almost... correct coefficient...
check the units of that term

bmore007
Oct3-05, 10:09 PM
i dont understand why that isnt correct


ViSin(30)*10 * ViCos(30)
Vi.5 * 10 * Vi .87
Vi 4.4

robphy
Oct3-05, 10:40 PM
that term should have a Vi^2

bmore007
Oct3-05, 11:05 PM
anychance you can give me a walk through numerically to the answer? i'm afraid that'll help me more then me struggling here

robphy
Oct3-05, 11:17 PM
In summary (up to this point):
ViSin(30)*10 * ViCos(30) = Vi^2 4.4

You've done fine with the coefficient, although you missed the fact that Vi is squared.
But you've gotten passed that. In other words, algebra (rather than arithmetic) is your problem.

Now, work on factoring "1/2(-9.8)(10/ViCos30)^2", which you should really write as (1/2)(-9.8)(10/ (ViCos30) )^2... especially if you try to plug something like this into your calculator.

bmore007
Oct3-05, 11:19 PM
unfortunately i'm not too good at more involved algebra like this :frown:


(1/2)(-9.8)(10/ (ViCos30) )^2


-4.9(100/Vi^2* .75)


so


4.4Vi^2 -4.9(100/.75Vi^2) :frown:

Integral
Oct3-05, 11:22 PM
I do not see anyway to give "a walk through numerically" with out doing the algebra first.

Is this the starting point:

1.05 = V_i Sin(30) * 10 * V_i Cos(30) + \frac {-9.8} {2} \frac {10} {{(V_i Cos(30))}^2}

bmore007
Oct3-05, 11:29 PM
yes that is the starting point

except it's (10/ViCos30)^2

the whole thing squared

bmore007
Oct3-05, 11:51 PM
n/m :frown: