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How can i factor this nicely, so that i can get a form to inverse-laplace transform it
\frac{0.25s}{s^2+0.25s+0.25}
so far i get this in denominator: (s+\frac{1}{8})^2+\frac{15}{64}
after completing the square, but then the last fraction is not a square of anything.... and i need a square there, the way everything else looks...
The denominator is already a square. I don't see how you got the other stuff. The answer should be a simple polynomial multiplied by an exponential.
Carl
I don't see a square there, if (a+b)^2 = a^2+2ab+b^2
this is a simple algebra thing... i guess i'm not seeing it :frown: could you show please?
How can i factor this nicely, so that i can get a form to inverse-laplace transform it
\frac{0.25s}{s^2+0.25s+0.25}
so far i get this in denominator: (s+\frac{1}{8})^2+\frac{15}{64}
after completing the square, but then the last fraction is not a square of anything.... and i need a square there, the way everything else looks...
Do not panic. 15/64 is the square of
\frac{\sqrt {15}}{8}
:smile:ehild
I don't see a square there, if (a+b)^2 = a^2+2ab+b^2
this is a simple algebra thing... i guess i'm not seeing it :frown: could you show please?
My mistake. I don't see anything wrong with the way you're doing this problem, so far.
Carl
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