View Full Version : Linear Algebra - Basis
Hello... im doing this problem with basis. Infact, im having a lot of problems understanding basis, i did every question in the text book and I still get seem to understand the idea of it.
So i was hoping somebody can help me with the whole idea about it.
Say, for example, how would i go abouts a question like this:
--Let F be a field and let V = F^3. Let
W = {(a1 a2 a3) E F^3 / 2a1 - a2 - a3 = 0 }
Find a basis for W --
If a question like that came on a test, id fail it - sad to say. It would also be good if somebody knows a good website or has sameple tests that covers this mataril so that i may get used to it.
Thanks
Brad Barker
Oct4-05, 06:56 PM
so any element in W can be represented like so:
w = (a1, a2, a3), where a1, a2, and a3 are arbitrary.
but W has the additional restriction that a1 = 1/2 (a2 + a3).
so
w= ( 1/2 (a2+a3), a2, a3).
w = a2 ( 1/2, 1, 0) + a3 (1/2, 0, 1). (it's easy to see that this is the same as above.)
so
w = span{(1/2, 1, 0), (1/2, 0, 1)}.
and that set {(1/2, 1, 0), (1/2, 0, 1)} is our basis.
ah, i miss these problems!
Gokul43201
Oct4-05, 07:04 PM
Keep in mind that the above is not the only basis.
Also, notice that the given vector space is nothing but a (generalization of a) plane through the origin in \mathbb{R}^3. Any pair of vectors in the plane will serve as a basis.
Hey.. i was just wondering about Brad Barkers post above...
he said that a1 = 1/2 (a2 + a3).
well.. shouldn't it be a1 = 1/2 (a2 - a3) ?
Does it make a difference?
Gokul43201
Oct5-05, 02:06 AM
No, you said "2a1 - a2 -a3 = 0"
That gives 2a1 = a2 + a3
oh that was my silly mistake.. but either way.. i still learned something :)
Hey.... what about the subspace...
U = (a+b+c=0/ a b c is in the Real Numbers)
How would you show the span of that.
Also, the comment Gokul43201 made, about the basis being the plane through the origin, how did he know that? I mean its a plane because of the two vectors, but how did he know that its through the origin?
iNCREDiBLE
Oct5-05, 03:54 PM
Also, the comment Gokul43201 made, about the basis being the plane through the origin, how did he know that? I mean its a plane because of the two vectors, but how did he know that its through the origin?
The general equation of a plane is Ax+By+Cz = D.
D = 0 \Longleftrightarrow the plane goes through the origin.
"and that set {(1/2, 1, 0), (1/2, 0, 1)} is our basis." Can that be a Basis for F^3? what is F (Feild)? isnt that the same as R, like R^3
Gokul43201
Oct6-05, 02:44 AM
The general equation of a plane is Ax+By+Cz = D.
D = 0 \Longleftrightarrow the plane goes through the origin.Also, for a plane to constitute a vector space with the usual vector addition, it must pass through the origin, since this point is the additive identity element.
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