Calculating Activated Speed in a Cylindrical Tube

[asa!!]

Hi to you all.i have an exercise i cannot solve.i think something is missing.

Cylindrical tube V=10L opened at the top has air with a temperature of T1=27 0C.We provide heat to the tube until the temperature reaches the value of T2=327 oC.A)we have to find the amount of air that leaves from the tube .
b)if we close at the top the tube and decrease the temperature to T3=127 oCwe have to find the activated speed.
c)what is the new number of particles.

i guess at the first question it requires the V of the air that leaves?I think that the pressure is steady as it is opened at the top the tube.so the pressure equals the pressure of the surrounding air.

How can i find the activated speed without knowing the consistency?i will assume it is one as we are talking about air?

thanks

 

[member 553083]

for your help.A) To calculate the amount of air that leaves from the tube, you need to know the volume of the air (V) and the density of the air (ρ). The mass of air that leaves from the tube can be calculated using the equation: Mass = V * ρ. b) To find the activated speed, you will need to use the ideal gas law. The equation is PV = nRT, where P is the pressure of the air, V is the volume of the air, n is the number of moles of gas, R is the universal gas constant and T is the temperature. Rearranging the equation yields: v = (nRT/P). c) The new number of particles can be calculated using the ideal gas law equation again. This time, you will need to know the new volume (V2) and the new temperature (T3). The new number of particles can be calculated using the equation: n2 = (PV2)/(RT3).