Solve Binomial Identities to Approximate Fresnel Zone Radius

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Discussion Overview

The discussion revolves around the derivation of the Fresnel zone radius approximation and its connection to the binomial theorem and Taylor series. Participants are exploring mathematical approximations and clarifying steps in the derivation process.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Exploratory

Main Points Raised

  • One participant expresses confusion regarding a mathematical jump in the derivation of the Fresnel zone radius approximation, suggesting it relates to the binomial theorem.
  • Another participant provides a LaTeX representation of the approximation, using the Taylor series to justify the simplification of the expression (D² + r²)^(1/2) when r << D.
  • A further participant requests more information about the Taylor series approximation and its derivation, indicating a willingness to verify the approximation through numerical examples.
  • One participant elaborates on the Taylor series, explaining its formulation and the concept of remainder or error term in the approximation.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the derivation steps, as there is ongoing clarification and exploration of the Taylor series and its application to the problem. The discussion remains unresolved regarding the initial confusion expressed.

Contextual Notes

Some assumptions regarding the conditions under which the approximations hold (e.g., r << D) are mentioned but not fully explored. The mathematical steps leading to the Taylor series approximation are presented, but the completeness of the derivation is not established.

mezarashi
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I was going the derivations for Fresnel zone radius approximation, and there was a jump in the math which I don't fully understand. If someone could take a look at this and help me figure. I was hinted that it had to do with the binomial theorem, but I have no idea >.<

Seems like LaTeX isn't working -_-
(D^2 + r^2)^(1/2)
if r << D
( D^2( 1 + (r^2)/(D^2) ) )^(1/2)

D1 + (r^2)/(2D^2) <--- ?
.
.
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Let's set this in Latex:
[tex](D^{2}+r^{2})^{\frac{1}{2}}=D(1+\epsilon)^{\frac{1}{2}}, \epsilon=(\frac{r}{D})^{2}[/tex]
If we now have [itex]\epsilon<<1[/itex], we have, by retaining the second term of the Taylor series about [itex]\epsilon=0[/itex]:
[tex](1+\epsilon)^{\frac{1}{2}}\approx{1}+\frac{\epsilon}{2}[/tex]

Thus, you have:
[tex](D^{2}+r^{2})^{\frac{1}{2}}\approx{D}+\frac{r^{2}}{2D}, \frac{r}{D}<<1[/tex]
 
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Hey awesome, thanks. Oh and Latex is working :P
Could you tell me a bit more about this "Taylor series" approximation or a link to its derivation, although I know this is true by punching some test numbers in the calculator. Thanks again.
 
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Okay, about Taylor series:
You know that given f(x) differentiable, you may write it as:
[tex]f(x)=f(0)+\int_{0}^{x}f'(t)dt(1)[/tex]
Now, use partial integration on the integral in the following manner:
[tex]\int_{0}^{x}f'(t)dt=(t-x)f'(t)\mid_{t=0}^{t=x}-\int_{0}^{x}(t-x)f''(t)dt(2)[/tex]
We also have:
[tex](t-x)f'(t)\mid_{t=0}^{t=x}=0*f'(x)+xf'(0)=xf'(0)[/tex]
thus, (2) may be written as:
[tex]f(x)=f(0)+f'(0)x+\int_{0}^{x}(x-t)f''(t)dt(3)[/tex]
where I have drawn the minus sign underneath the integral sign.
We may now rewrite (3) by noting:
[tex]\int_{0}^{x}(x-t)f''(t)dt=\frac{x^{2}}{2!}f''(0)+\frac{1}{2!}\int_{0}^{x}(x-t)^{2}f'''(t)dt[/tex]
that is:
[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{1}{2!}\int_{0}^{x}(x-t)^{2}f'''(t)dt(4)[/tex]
The emerging series has the form, for an infinitely differentiable function:
[tex]f(x)=\sum_{n=0}^{\infty}\frac{f^{(n)}(0)}{n!}x^{n}[/tex]
where [itex]n![/itex] is the factorial 1*2*3...*n (0!=1), and [tex]f^{(n)}[/tex] denotes the n'th derivative of f. (f is considered its own 0'th derivative).

That infinite series is called the Taylor series of f with respect to 0, a finite, truncated version of it is called a Taylor series approximation to f.

If we have the identity containing f(x) on the left-hand side and a finite sum and the integral on the right-hand side (for example our (4)), we call the integral "the remainder", or "error term".
 
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