Supermarket Ramp Design: Finding the Optimal Slope

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Homework Help Overview

The discussion revolves around the design of ramps in a supermarket, specifically focusing on determining an optimal slope for a ramp that customers can use to push grocery carts. The original question involves calculating whether a 5-degree slope is too steep for a 30-kg cart, considering a friction coefficient of 0.10 and a maximum acceptable force of 50 N.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of a specific formula to determine the force required to push the cart up the ramp. There are mentions of using substitutions for trigonometric functions and solving a quadratic equation. Some participants express difficulty in understanding the steps involved and seek more detailed guidance.

Discussion Status

There is an ongoing exchange where participants are attempting to clarify the mathematical approach needed to solve the problem. Some have provided suggestions for substitutions and methods, while others are seeking further assistance and expressing their struggles with the material.

Contextual Notes

Participants have noted the importance of showing their work and engaging with the problem-solving process, as well as the need to adhere to forum guidelines regarding homework help.

tman1
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here was the original question. in the design of a super market, there are to be several ramps connecting different parts of the store. cusomers will have to push grocery carts up the ramps. An engineer has done a survey and found that almost no one complains if the force require is no more that 50 N. Will a slope of 5 degrees be too steep, assuming a 30-kg grocery cart (full of groceries)? Assume friction can be accounted for by a coeffecient of 0.10.

we found that 5 degrees is too high. the new question requires us to find out the actual degree. How would i find it help!

i forgot to add the the formula that should be used is as follows
Fapp= (coefficient of friction x mass x gravity x cos thada) + (mass x gravity x sin thada)
i need help with the trig identities part more

PLZ solve full answer please
 
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Your formula is,

Fapp = mg(sinø + μcosø)

There are two ways of solving this - analytically or using an approximate method, e.g. Newton's method.

Analytically
=========
Use the substitutions,

sinø = 2t/(1+t²)
cosø = (1-t²)/(1+t²)

where

t = tan(ø/2)

You will end up with a quadratic in t. Solve for t, then find ø = 2*arctan(t).

Or, if you have done Newton's method, you could do it that way.
 
ty

thatnks for ur help but i still don't understand what to do so i was wondering if u could coach me through it
 
Have you made the substitutions for sinø and cosø in the formula Fapp = mg(sinø + μcosø) ?
 
yes

yes i did but i can't solve for either cos thada or sin thada
 
You have to substitute for
sinø = 2t/(1+t²)
and
cosø = (1-t²)/(1+t²)

In Fapp = mg(sinø + μcosø), replace sinø by 2t/(1+t²) and replace cosø by (1-t²)/(1+t²).
This will give you a quadratic int t, which you then solve for, not for ø.
See my earlier post, #2.
 
im really slow

can u please write out step by step what to do. I am really slow sir please
 
tman, this is a help forum and I have given you a lot of help and advice, but you have to something yourself.

Have you read the sticky at the top of this forum ? If not, will you please do so.

I have given you adivice and help, now it is up to you to do some work and show me what you have done.

All you have to do is make a substitution; show me your work and I will comment upon it.
 
thx

thanks for ur hellp and all and I am sorry i was a pest
i solved it differently from how u showed me tho
 

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