What Happens When a Person Touches a Live Wire?

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A person with a body resistance of 13.0 kiloohms touches a power supply with a potential difference of 16.0 V and an internal resistance of 2100 ohms. The calculated current through the body is 1.06×10-3 A using the formula I = V/(Rp + Ri). To find the power dissipated in the body, the voltage drop across the body must be determined, not the total voltage of the circuit. The correct approach involves calculating the voltage drop across the person's resistance to accurately compute power dissipation.

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Suppose that a person has a resistance of 13.0 kiloohms as part of a circuit which passes through his hands. This person accidentally grasps the terminals of a power supply with a potential difference of 16.0 V.
PART A:If the internal resistance of the power supply is 2100 ohms , what is the current through the person's body?
I calculated the current to be 1.06×10−3 A by using the equation I = V/(R_p + R_i)
PART B: To find the power dissipated in his body I thought you use the equation P = I*V so P =(1.06*10^-3 A)*(16.0V) which gave me 1.70*10^-2 which is wrong. What I am doing wrong??
Thank you for your help
 
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I think V isn't 16 V, since you want the voltage drop across his body, not the whole circuit
 

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