Find Coordinate Vector of A relatvie to {A_1, A_2, A_3, A_4, A_5, A_6}

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The discussion focuses on finding the coordinate vector of matrix A relative to the basis matrices A_1 through A_6. The user proposes using the reduced row echelon form (RREF) method to solve the system of equations derived from the linear combination of the basis matrices. The equations formed from the components of A lead to a system of six equations with six unknowns, which can be represented as a matrix equation for further analysis. The approach is confirmed as valid, emphasizing the need to correctly set up the matrix equation for accurate results.

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niteshadw
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How do you find the coordinate vector of

A =
1 1
1 2
2 2

relatvie to the basis {A_1, A_2, A_3, A_4, A_5, A_6}?

A_1 =
3 6
3 -6
0 0

A_2 =
0 -1
-1 0
1 1

A_3 =
0 -1
-2 -2
2 1

A_4 =
1 0
1 3
0 2

A_5 =
1 0
0 1
2 2

A_6 =
2 0
1 4
-1 3

Is it jus taking each of the matrix and making one large one and doing rref so I get:

88/157(A_1) + 23/157(A_2) + etc...?

I don't think its working out though...not even sure if its the correct thing to do...thanks
 
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If I understand your notation correctly, you are looking for numbers x1, x2,..., x6 so that
x1A1+ x2A2+ ...+ x2A2= A.

Looking at the individual components, that gives
3x1+ x4+ x5+ 2x6= 1,
6x1- x2- x3= 1, etc.
6 equations in 6 unknowns. Of course, you can set that up as a matrix equation itself.
 

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