Need to find a convergent value

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SUMMARY

The discussion centers on the convergence of the sum \( s = \sum_{k=1}^{\frac{x}{j} - 1} k^{n} j^{n+1} \) as \( j \) approaches 0. The established conclusion is that the sum converges to \( \frac{x^{n+1}}{n+1} \). The user seeks clarification on deriving this result and relates it to the concept of Riemann sums, specifically expressing \( s \) in terms of \( s = \sum_{k=1}^{N-1} x_k^n \Delta x \), where \( N = \frac{x}{\Delta x} \) and \( x_k = k \Delta x \).

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Given this sum

[tex]s = \sum_{k = 1}^{{\frac{x}{j}} - 1} k^{n}j^{n+1}[/tex]

x and n are constants

and x/j is a positive integrer and k is an integrer

To what value s converges as

[tex]{j}{\rightarrow}{0}[/tex]
?

Edit: I have found that the awnser is [tex]\frac{x^{n+1}}{n+1}[/tex], but i do not know how to obtain this...
 
Last edited:
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What do you recognize if I write
[tex]s = \sum_{k=1}^{N-1} x_k^n \Delta x[/tex]
where [tex]N = x/(\Delta x)[/tex] and [tex]x_k = k \Delta x[/tex]? What about a Riemann sum?
 

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