How Fast Must a Volleyball Be Hit to Clear the Net and Reach the Back Line?

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SUMMARY

The discussion focuses on calculating the minimum and maximum horizontal velocities required for a volleyball to clear a net height of 2.24 meters while being hit from a height of 3 meters and a distance of 8 meters from the net. The minimum velocity needed to clear the net is determined to be approximately 21.05 m/s, based on projectile motion equations. The calculations involve using the vertical motion equation to find the time of flight and then applying it to horizontal distance to derive the required velocities. The approach for determining the maximum velocity to strike the back line involves similar algebraic methods with adjusted parameters.

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Simple Projectile Question

there is a volleyball net 2.24m high (the court is 9m by 9m on both sides), and you hit the ball while being 3m in the air, you are 8m away from the net, if the initial velocity is horizontal find
A)what minimum velocity must the ball have to clear the top of the net
B)what maximum velocity can it have if the ball is to strike the the back line on the other side of the net?
Work...
V0 = ?
X-X0 = 8m
Y-Y0 = 0.76m
(theta) = 84.57
----------------------------------
Vy2 = -2g(y-y0)
Vy = 3.76m/s
Vy = V0sin(theta) - gt
Vy/-g = t
t = 0.38
X-X0 = V0x(t)
8m = V0x(0.38s)
V0x = 21.05 m/s?not likely
 
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I haven't run through the numbers, but your procedure looks good for part a.

You need to do something similar for part b. Just as in part a when you asked yourself what must [itex]V_{0x}[/itex] be in order to clear the net, now you have to ask yourself what must [itex]V_{0x}[/itex] be in order to not go past the edge of the court. The algebra is going to be the same, but with different numbers.
 

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