Analyzing Work and Potential Energy for a Uniform Force at an Angle µ

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SUMMARY

The discussion focuses on calculating the minimum work required to move a point mass under a uniform force at an angle µ to the vertical, represented as F = ma sin µ i - ma cos µ j. The first part of the question seeks the work done in vector notation, while the second part addresses the direction in which potential energy remains constant. Participants confirm that the force is conservative, allowing for path independence in work calculations, and suggest resolving the force into orthogonal components to simplify the analysis.

PREREQUISITES
  • Understanding of vector notation in physics
  • Knowledge of conservative forces and work-energy principles
  • Familiarity with Euclidean geometry for vector analysis
  • Basic concepts of potential energy in physics
NEXT STEPS
  • Study the principles of conservative forces and their implications on work
  • Learn how to resolve forces into orthogonal components in vector analysis
  • Explore the concept of potential energy and its relation to force direction
  • Practice problems involving work done by forces at angles, specifically using vector notation
USEFUL FOR

Students and professionals in physics, particularly those focusing on mechanics, vector analysis, and energy concepts. This discussion is beneficial for anyone looking to deepen their understanding of work and potential energy in the context of forces acting at angles.

jd102684
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Hello, I need some help on a two part question. Thanks in advance!

Consider a uniform force, similar to the gravitation force but pointing at an angle µ to the vertical direction, F = ma sin µ ¡ ma cos µ j (i and j represent vector notation...)

1) What is the minimum work required to move a point mass with mass equal to m from the origin (0,0) to a point P (x,y)? (answer in vector notation in terms of µ)

2) in what direction r (also a vector) is the potential energy constant?


Thanks so much for all your help!


EDIT: I forgot to post my current work. I've tried to mess with changing the axis so I can treat the force like gravity. I know that the force is conservative, so the work required to move the mass from point A to point B is the same no matter what path is taken. I'm just really having trouble getting an answer in terms of the angle in vector notation... As for part 2, I would guess it would be in the direction oposite of the uniform force being applied, but when i submitted what i got for that answer, it came back as wrong.
 
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You have the force resolved into orthogonal components, so for all practical purposes you can treat them as independent of each other. Work out the work in the i direction and the work in the j direction, then add them. You'll get the direction with a little Euclidean geometry - just make a sketch and I think you'll see what I mean.
 
Thanks, that did help! I got the first part, but before I try to crank out an answer to the second part of the question can you tell me if my line of thinking is correct as far as what I say in the original post? Maybe give me a boost in the right direction again? Thanks so much!
 

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