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jamjar
Oct19-05, 01:44 PM
Hi,
I've come across this series and I'm not sure in which direction I should be looking to get an equation for the sum. I've tried some simple methods but have come up blank.
\sum\limits_{n = 0}^{n - 1} {nr^n }
Can anyone give me a nudge in the right direction?

Galileo
Oct19-05, 02:14 PM
Does it look like another series you know? Can you find some way to relate the two?

BTW: Your index is n, but you are summing to n-1. So n is doing double duty. I suppose you mean:
\sum_{k=0}^{n-1}kr^k

hustler
Oct19-05, 02:25 PM
Perhaps the geometric series?

jamjar
Oct19-05, 03:02 PM
I can't see how to relate the two.
The extra multiplication by k is making it difficult.

Galileo
Oct19-05, 03:50 PM
Okay, here's where my ignorance about the contents of a pre-calculus class may come into play, but...the terms in the geometric series have r^k. Is there anything, some operation, you can do to each of the r^k terms to make it look like more or less kr^k?

hustler
Oct19-05, 04:25 PM
hmmmmmmmmmmmm

jamjar
Oct19-05, 04:27 PM
I could differentiate perhaps?
I'm not sure what operations I can use within the summation.

Galileo
Oct19-05, 05:01 PM
I could differentiate perhaps?

That's a good idea!
What'd you get if you differentiate a geometric sum?

jamjar
Oct19-05, 07:34 PM
Well, I worked it out from there.
I just wasn't expecting to get any differentiation in pre-calc.
Thanks for the help :smile:

shmoe
Oct19-05, 09:01 PM
You can do it without differentiation if you like. Write it as a double sum and swap order of summation. You could also think of this as writing it as a sum of geometric series (all of different lengths).