Solving Linear Transformation Problem: L((7,5))^T Value Calculation

Click For Summary

Homework Help Overview

The discussion revolves around a linear transformation problem in Linear Algebra. The original poster seeks to determine the value of L((7,5))^T given specific outputs for L applied to other vectors.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of the linear operator and the implications of the transformation matrix. There are attempts to express (7,5) as a linear combination of the given vectors (1,2) and (-1,1). Questions arise about the meaning of transposition and the clarity of the problem setup.

Discussion Status

Some participants have offered guidance on using linear combinations and the properties of linear transformations. There is an ongoing exploration of different combinations and their validity, with no explicit consensus reached on the correct approach.

Contextual Notes

Participants note potential confusion regarding the transposition notation and the specific linear combinations used. There is also mention of discrepancies between calculated results and textbook answers, indicating a need for further clarification on the problem's setup.

electricalcoolness
Messages
18
Reaction score
0
I have a question regarding a math problem that I do not know how to go about solving.

Let L: R^2 ---> R^2 be a linear operator. If L((1,2)^T)) = (-2,3)T
and L((-1,1)) = (5,2)^T determine the value of L((7,5))^T

Any insight would be much appreciated.
 
Physics news on Phys.org
L((1,2)^T)) = (-2,3)T

Just to make things clear, L is your function, and T is what in this case? ...And..what class is this for?
 
T mean Transposed, sorry I made a typo.


Let L: R^2 ---> R^2 be a linear operator. If L((1,2)^T)) = (-2,3)^T
and L((-1,1)) = (5,2)^T determine the value of L((7,5))^T

This is some Linear Algebra homework I am stuck on.
 
electricalcoolness said:
T mean Transposed, sorry I made a typo.
Let L: R^2 ---> R^2 be a linear operator. If L((1,2)^T)) = (-2,3)^T
and L((-1,1)) = (5,2)^T determine the value of L((7,5))^T
This is some Linear Algebra homework I am stuck on.

k. Well, I'll assume (-1,1) is transposed also.

One way you can do this is by looking at the transformation matrix of L. Let's say its [x y]. Matrix multiplying ur vector by the transformation matrix should get you your answer. In this case, the values of x, y are not given but the answers are (by answers, i mean images). You should see that this becomes a problem of solving two equations.
 
I still a little confused, please can you make it a little more clear?
 
Try writing (7,5) as a linear combination of (1,2) and (-1,1). How will this help?

PS. it's ok to think of your vectors as row vectors, you could then leave out the transpose. Makes things a little neater in text.
 
shmoe's idea is on the right track...sorry, but I was way off, i think.
 
Try writing (7,5) as a linear combination of (1,2) and (-1,1). How will this help?

I did, but I still don't see how it would help?
 
well now that you've done that consider the definition of A linear transformation.

A function L: R^n--->R^m is called a linear transformation or linear map if it satisfies

i) L(u+v)= L(u) + L(v) for all u,v in R^n
ii) L(cv)= cL(v) for all v in R^n, and scalar c

Using both, this definition and the combination you just made you should be able to get your answer.
 
  • #10
I just realized that the combination I created is one of a few different combinations, does that matter which combination I use? I still can't get an answer. Or rather, I still can't get the answer that matches the books. is my linear combination correct?
where x1 = (1,1) and x2 = (2,-1)

4*x1 + 3*x2 = 7
3*x1 + (x2) = 5

where x1 and x2 have been taken from the (1,2) and (-1,1)I might have figured something out,
if I allow for a matrix multiplied by some other matrix, is that how i come about my answer?
 
Last edited:
  • #11
I really thank you guys for your help and patience with me.

I think I figured out my answer, and it all makes sense. You guys are awsome.:smile: :approve: :approve: :approve:
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 24 ·
Replies
24
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K