Net gravitational force problem in a straight line?

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SUMMARY

The net gravitational force exerted on a 0.100-kg uniform sphere by two other uniform spheres was calculated using Newton's law of universal gravitation. The forces were computed as F_1 = 1.854 x 10^-10 N and F_2 = -2.085 x 10^-10 N, resulting in a net force of F_x = -2.31 x 10^-11 N. The final magnitude of the gravitational force is confirmed to be 2.31 x 10^-11 N, with no force acting in the y-direction.

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erik-the-red
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Question

In the figure attached, what is the magnitude of the net gravitational force exerted on the 0.100-kg uniform sphere by the other two uniform spheres? The centers of all three spheres are on the same line.

So, I'm thinking [tex]F_1=(Gm_1m_2/r_1^2)[/tex] and [tex]F_2=Gm_1m_3/r_2^2[/tex].

[tex]F_1=(6.673*10^-10)(.100)(10.0)/(.600^2)[/tex]
[tex]F_2=(6.673*10^-10)(.100)(5.00)/(.400^2)[/tex]

[tex]F_1=1.854*10^-10[/tex]
[tex]F_2=-2.085*10^-10[/tex]

[tex]F_x=F_1+F_2=-2.31*10^-11[/tex] N

I don't think there is a force in the y-direction, so [tex]F=\sqrt(F_x^2)=2.31*10^-11[/tex] N.

Is this correct?
 

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Looks good to me. (You did have a few typos in some of your steps.)
 

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