Electric field is zero at center of cavity?

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SUMMARY

The discussion centers on the application of Gauss's Law in determining the electric field within a cavity inside a sphere. While Gauss's Law can be applied, it does not directly conclude that the electric field is zero; it indicates that the electric flux through a closed surface is zero when no charge is enclosed. To ascertain the electric field's value, one must consider the symmetry of the electric field and the Gaussian surface, leading to the conclusion that zero enclosed charge results in a zero electric field at the cavity's center.

PREREQUISITES
  • Understanding of Gauss's Law
  • Familiarity with electric field concepts
  • Knowledge of symmetry in electric fields
  • Ability to analyze Gaussian surfaces
NEXT STEPS
  • Study the implications of Gauss's Law in electrostatics
  • Explore electric field symmetry and its effects on field calculations
  • Learn about different types of Gaussian surfaces and their applications
  • Investigate the relationship between electric flux and electric field strength
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Students of physics, electrical engineers, and anyone studying electrostatics who seeks to deepen their understanding of electric fields and Gauss's Law applications.

positron
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Does an electric field exist in the center of a cavity inside a sphere? Can I just apply Gauss's law and say that because no charge is enclosed, the electric field is zero? If not, why can Gauss's law not be applied?
Thanks,
positron
 
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positron said:
Does an electric field exist in the center of a cavity inside a sphere? Can I just apply Gauss's law and say that because no charge is enclosed, the electric field is zero? If not, why can Gauss's law not be applied?

Gauss' law can be applied ; but it doesn't say that the E-field is 0, it only says that the flux of the E-field through a closed surface must be 0. So as long as one part is "incoming" and another part is "outgoing" then that's still ok.

cheers,
Patrick.
 
Gauss' Law only tells you about the flux of the electric field vectors on that Gaussian surface... You need to appeal to additional information, e.g. symmetries of the field and/or of the Gaussian surface, to deduce information about the field vectors themselves (i.e., derive an expression for E on that surface). In other words, for your problem, you have to argue [say, using Gauss and symmetry... and possibly a sequence of Gaussian surfaces] that zero enclosed charge implies zero electric field at the center.
 

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