Units of Gradient for s x s vs m

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The discussion centers on the units of the gradient when plotting time squared (s x s) over distance in meters. It establishes that the gradient of this plot is expressed as s²m⁻¹, which is the reciprocal of acceleration. The conversation also reinforces that when plotting velocity (ms⁻¹) over time (s), the gradient yields acceleration (ms⁻²). This clarification aids in understanding various related physics problems.

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If we plot velocity in ms-1 over time in seconds, the gradient of the curve is acceleration or ms-2.

If we plot time squared i.e. s x s over distance in metres, what are the units of the gradient? :redface:
 
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polyperson said:
If we plot velocity in ms-1 over time in seconds, the gradient of the curve is acceleration or ms-2.
If we plot time squared i.e. s x s over distance in metres, what are the units of the gradient? :redface:
velocity over time gives: [tex]\frac{ms^{-1}}{s} = ms^{-2}[/tex]
similarly,
time squared over distance gives:[tex]\frac{s^2}{m} = s^2m^{-1}[/tex]
which is just the reciprocal of acceleration.
 
Thank you Fermat, that makes sense for me to a host of other problems I've been having!
 

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