Solving Physics Problem: Hot & Cold Liquids w/Formulas

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SUMMARY

The discussion focuses on solving a physics problem involving the mixing of hot and cold liquids using the formula T = (ah + bc) / (a + b). The user presents two scenarios with specific ratios of hot tea to cold milk: 9:1 resulting in a mixture temperature of 117 degrees, and 2:1 resulting in a temperature of 96 degrees. The solution involves setting up two equations based on these ratios and temperatures, simplifying them, and using substitution to find the initial temperatures of the hot tea (h) and cold milk (c).

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High school students studying physics, educators teaching thermodynamics, and anyone interested in applying algebra to real-world problems involving temperature and mixtures.

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Hello, I am just starting Physics. ( Sophmore in high school)

I need some help, understanding and solving this problem.


When you mix hot and cold liquids you can find the temperature of the mixture by using the formula T= ah+bc divided by a+b, where T is the temperature of the mixture, h is the temperature of the hot liquid, c is the temperature of the cold liquid, a and b respresent the amounts of hot and cold liquids. Suppose you mix hot tea and cold milk in a ratio a:b of 9:1 and find that the temperature of the mixture is 117degrees You then change the trea:milk ratio to 2:1 and the temperature drops 96degrees. Find the initial temperatures of the tea and Milk.

Again, I can solve it Logically. But using Formula's ( showing your work ) I am not very found of..

Can someone show how to go about this. Thanks!
 
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Can't you solve it using simple algebra?

For your first ratio, you would just plug in your values, and it would look something like this:

117=(9h/10)+(c/10)
for the second:
96=(2h/3)+(c/3)

Simplify them and work them out separately, until you have both of the variables (h and c) on one side for both equations.

You can then have "h" equal something ±c, then in the second equation inject what h equals into h's place. Solve the equation for c, then solve the first equation as you would a one-variable algebraic equation.
 
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