- #1
DKPeridot20
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*sigh* I'm SURE there is a perfectly reasonable solution to this problem, unfortunately for me it remains just beyond the next horizon. 
The green block (2 kg) is falling at a speed of 29. m/s and is 3.0 meters above the spring. The spring constant is 4.00E3 N/m. What is the maximum hsight that the block will rise after it hits and leaves the spring (use g=9.81 m/s^2)?
I have
1) found v when it hits the spring by v^2 = Vnot^2 + 2a(change in)x
2) found distance compressed by (final rearrangement) d = v(sq rt of)m/k
3) found v on the way up by (final rearrangement)
v = (sq rt of) kd^2/2 - mgd
4) found displacement on the way up by (final rearrangement)
(change in)x = v^2 - vnot^2 / 2a
and I come VERY close to the right answer, but not quite there. What am I doing wrong and how can I fix it, please?
Also, how does the change in gravitational potential energy apply in this situation and what exactly is it?
Thanks so much.
The green block (2 kg) is falling at a speed of 29. m/s and is 3.0 meters above the spring. The spring constant is 4.00E3 N/m. What is the maximum hsight that the block will rise after it hits and leaves the spring (use g=9.81 m/s^2)?
I have
1) found v when it hits the spring by v^2 = Vnot^2 + 2a(change in)x
2) found distance compressed by (final rearrangement) d = v(sq rt of)m/k
3) found v on the way up by (final rearrangement)
v = (sq rt of) kd^2/2 - mgd
4) found displacement on the way up by (final rearrangement)
(change in)x = v^2 - vnot^2 / 2a
and I come VERY close to the right answer, but not quite there. What am I doing wrong and how can I fix it, please?
Also, how does the change in gravitational potential energy apply in this situation and what exactly is it?
Thanks so much.