Inclined Plane Newton's Third Law

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Homework Help Overview

The problem involves a box sliding down a 39° inclined plane with a given acceleration of 1.32 m/s². The objective is to determine the coefficient of kinetic friction between the box and the ramp.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to begin due to multiple unknowns, mentioning the normal force in relation to gravitational components. Other participants discuss the relationship between net acceleration and the forces acting on the box, including friction and gravitational components.

Discussion Status

Participants are exploring various interpretations of the problem, with one providing a detailed breakdown of the forces and accelerations involved. There is no explicit consensus, but some guidance has been offered regarding the relationship between the forces acting on the box.

Contextual Notes

There is a mention of the assumption that mass remains constant, and the discussion includes the need to clarify the roles of different forces acting on the box as it slides down the ramp.

hshphyss
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Can anyone help me with this problem? thank-you

A box slides down a 39° ramp with an acceleration of 1.32 m/s2. Determine the coefficient of kinetic friction between the box and the ramp
 
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Please show what you've done so far.
 
I don't know where to start because of the many unknwns. I know that mgcos39=N.
 
I m sorry, if its too late!

Just registered myself...so i don't know if the answer wud still help u!
in ur quest...the acceleration given is the net acceleration actin on the object that's slidin down the ramp. so we know that the difference between the acceleration actin horizontally down the ramp and the acceleration actin opposite to it(acceleration occurin in the direction of friction) has to be 1.32m/s/s.
all we need ta do now is to find the acceleration actin horizontally down the ramp. which has ta be 9.8 times sin39= 6.2m/s/s
as i already mentioned the frictional acceleration has ta be 1.32 less than 6.2(6.2-1.3=4.8m/s/s
so now we know the acceleration in the direction of kinetic friction. acceleration occurin in the direction of normal is balanced by the acceleration towards the gravity. so if we find the y component of gravity...we have the normal(as it has ta be the same!
thats 9.8 cos39=7.6m/s/s
co-eff of friction= accl towrds friction/acceleration normal
4.8/7.6=.64
thats bout it i guess...generally we use force instead of acceleration...but in this prob we assume mass constant!
if u have further doubts...u can always post it, it will help me learn more...
take care
 
wow thank-you so much
 

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