Physics Problem: Brick Thrown From Building Height

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Homework Help Overview

The problem involves a brick thrown upward from the top of a building at an angle, with a specified initial speed and total time in the air. The goal is to determine the height of the building based on the motion of the brick.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of the problem as one of projectile motion, with an emphasis on analyzing the first half of the brick's trajectory. Questions arise regarding the assumptions made about the brick's landing point and the interpretation of the total time in the air.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the assumptions made about the trajectory and landing of the brick. Some guidance has been offered regarding the approach to solving the problem, but no consensus has been reached.

Contextual Notes

There are concerns about the assumptions regarding the brick's landing position and the implications of the total time of flight on the calculations. Participants are navigating the constraints of the problem while adhering to forum guidelines regarding solution sharing.

Physicsdummy_101
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A brick is thrown upward from the top of a builidng at an angle 25 degrees to the horizontal and with an initial speed of 15m/s. If the brick was in the air for three seconds how tall is the building
 
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So, what have you done so far?
 
giv this a try!

this probs is a projectile motion probs where the object is launched at an angle from horizontal surface. i wud rather u to c this probs in the first half of its motion. when the total time taken for the object to travel up to the height of the buildin and then come back to the position that it started from is 3 sec...it has ta take 1.5 sec to reach to the maximum height of the buildin where the y component of the velocity has to be 0. now when u divide the prob and solve it imaginin the first half...its much less complicated!
the initial y-velocity will be- 15 sin25= 6.3 m/s
to find the max height...we will use the formula- y= ut + .5 at^2
6.3(1.5)+.5 (9.8)(2.25)
=1.6 m
i will feel much better if the answer come out rite...if not we will try solvin it in other ways!
take care
 
ritz:
(1) Please do not provide complete solutions. It's a violation of the PF Guidelines: https://www.physicsforums.com/showthread.php?t=5374
(2) Your solution assumes the projectile lands on the roof of the building! You won't find the height of the building with that assumption. :wink:
 
doc...i havnt assumed that the ball lands on the buildin...just that it crosses the buildin! so when u consider just one part of the problem...where the ball moves up and reaches the highest point...u cud solve the probs in much easier way...try urself! i m sure it will make much more sense...
and thnx lettin me know the rules...appreciate that!
cheers!
 
ritz said:
doc...i havnt assumed that the ball lands on the buildin...just that it crosses the buildin!
Seems to me like you did. You said this:
ritz said:
when the total time taken for the object to travel up to the height of the buildin and then come back to the position that it started from is 3 sec
But that 3 sec total time must be the time for the brick to go from rooftop to highest point and then down to the ground, else the problem won't make sense. (The time it takes to get to the highest point is not 1.5 sec.)
 

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