Inertial Disk Lab: Physics 11 H Experiment

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SUMMARY

The discussion centers on calculating the tension in a string attached to an inertial disk in a Physics 11 H lab experiment. The diameter of the hub is 76 cm, and the disk measures 25 cm. The participant calculated the acceleration of a 69.9-gram weight to be 0.039 m/s², but confusion arose regarding the correct application of tension formulas and the role of the hub's radius. Key insights include the necessity of using the gravitational constant g = 9.81 N/kg and understanding that the sum of forces determines the mass's acceleration.

PREREQUISITES
  • Understanding of Newton's Second Law (T=ma)
  • Basic principles of rotational motion
  • Knowledge of gravitational force (g = 9.81 N/kg)
  • Familiarity with kinematic equations
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  • Study the relationship between tension and gravitational force in rotational systems
  • Learn how to apply kinematic equations to analyze motion
  • Explore the effects of radius on tension in circular motion
  • Investigate the principles of inertial disks and their applications in physics experiments
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Students in Physics courses, particularly those studying mechanics, educators teaching physics concepts, and anyone interested in experimental physics involving rotational dynamics.

agentd00nut
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Ok, in my Physics 11 H class we did a lab with an inertial disk (a disk with a hub in the center, a string is attached to the hub like a huge half a yoyo where the yoyo is stationary and weights are the fingers falling down) and i need to be able to calculate the tension in the string for various weights attatched to the end of the strings. I am pretty sure that just using T=ma will work or maybve do something with tension but i don't know where the radius of the hub comes into play and the weight of the disk, any help would be greatly appreciated the diamter of the hub is 76 cm and the disk is 25 cm i calculated the acceleration of a 69.9 gram weight to be .039 m/s^2 and it falls 1.75 meters in a 6.69 second period so using my logic t= .669 * .039 is that correct?
 
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let's see, if it starts from v=0 and moves 1.75 m in 6.69 s,
its avg velocity is 0.2616 m/s .
the final v = .5312 m/s , same as its change of velocity.
the acceleration is 0.0782 m/s/s . Where's your .039 from?

the mass (0.0669 kg !) is pulled down by gravity, up by Tension.
Most places use g = 9.81 N/kg unless you know yours better.
The SUM of Forces cause the mass to accelerate.
 

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