Proving the Spanning Property of Linearly Independent Columns in Lin Alg

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SUMMARY

The discussion centers on proving that the columns of the matrix \( A^2 \) span \( \mathbb{R}^n \) when the columns of matrix \( A \) are linearly independent. It is established that if the columns of \( A \) are linearly independent, then \( A^2 \) maintains this property, leading to the conclusion that \( \text{Span}(\vec{a}_1, \vec{a}_2, \ldots, \vec{a}_n) = \mathbb{R}^n \). Furthermore, it is confirmed that an \( n \times n \) matrix \( B \) with linearly independent columns implies that \( B \) is invertible and that the equation \( Bx = 0 \) has only the trivial solution.

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Problem: Explain why the columns of [itex]A^2[/itex] span [itex]\mathbb{R}^n[/itex] whenever the colums of A are linearly independent.

By the theorem given in that section of the text, it is a logically equivalent fact that if the columns of [itex]A^2[/itex] are linearly independent, then they span [itex]\mathbb{R}^2[/itex] or
[tex]\mathbb{R}^2=Span( \vec{a}_1 , \vec{a}_2 )[/tex].

How do I expand this definition from [itex]\mathbb{R}^2[/itex] to [itex]\mathbb{R}^n[/itex]?
 
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If B is an nxn real matrix, then what can you say about whether or not its columns span Rn if its columns are linearly independent. Don't worry about B being a matrix. You know that it since it is nxn, it gives you n linearly independent columns, so you should know something about whether those columns span Rn. Once you know this, you should be able to say something about conditions on x if Bx = 0. You should also be able to say something about the invertibility of B. Can you get this far?
 

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