Finding Eignevalues & Eigenvectors of A⁻¹ Without Direct Computation

Click For Summary
SUMMARY

The discussion focuses on finding the eigenvalues and eigenvectors of the inverse matrix A⁻¹ without direct computation. It establishes that if A has eigenvalues 1, 2, and 3 with corresponding eigenvectors [1,1,0], [0,1,0], and [3,-1,2], then the relationship A⁻¹Ax = λA⁻¹x can be utilized to derive properties of A⁻¹. The key conclusion is that the eigenvalues of A⁻¹ are the reciprocals of the eigenvalues of A, confirming that if λ is an eigenvalue of A, then 1/λ is an eigenvalue of A⁻¹.

PREREQUISITES
  • Understanding of eigenvalues and eigenvectors
  • Familiarity with matrix operations, specifically matrix inversion
  • Knowledge of linear algebra concepts
  • Ability to manipulate equations involving matrices
NEXT STEPS
  • Study the relationship between eigenvalues of a matrix and its inverse
  • Learn about the properties of eigenvectors in linear transformations
  • Explore the implications of the Cayley-Hamilton theorem
  • Investigate computational methods for finding eigenvalues and eigenvectors
USEFUL FOR

Students and professionals in mathematics, particularly those studying linear algebra, as well as anyone involved in computational mathematics or theoretical physics.

brad sue
Messages
270
Reaction score
0
Hi, I need help for this problem:
Find the eignevalues and eingenvectors for the matrix below. DO NOT compute them directly by computing the matrix:
A-1

We need to find some kind of demonstration to see if the eignevalues of A-1 are the same, opposite or inverse (or whatever) as those of matrix A
Suppose that the eignvalues are 1,2,3 and the eignvectors are [1,1,0], [0,1,0],[ 3,-1,2] ( in columns
Thank you
B
 
Physics news on Phys.org
If [tex]Ax= \lambda x[/tex] Then [tex]A^{-1}Ax= A^{-1}\lambda x= \lambda A^{-1}x[/tex].

What does that tell you?
 
HallsofIvy said:
If [tex]Ax= \lambda x[/tex] Then [tex]A^{-1}Ax= A^{-1}\lambda x= \lambda A^{-1}x[/tex].
What does that tell you?
I have been thinking but I really do not know.
Can we say that I ( indentity matrix)= lambda*A-1??
I does make me go far doesn't it?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
3
Views
2K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K