yet another question on circuits!

[QueenFisher]

i've been given this circuit, i know the e.m.f. and internal resistance, it has 2 resistors connected in parallel so i can work out Rtotal, but i need to work out the current through one of the resistors. can anyone point me in the right direction?
thanks :biggrin:

[verty]

Well, once you know R you can calculate the total current. With the current, you can calculate the volt-drops certain resistances, etc. That's generally the approach to take.

[QueenFisher]

so do i take the e.m.f. as being the supply voltage in this case? cos i can't think of any other way to find it

[ranger]

The internal resistance [of the battery] acts as if it were a resistor in series with the battery. You could find the ternimal voltage.
V_{ab} = \varepsilon - Ir

\varepsilon = Emf
r = internal resistance

USing ohms law we get.
IR = \varepsilon -Ir

Where R is the 2 resistors in parallel.

I'm sure you can take it from here.