A passenger rushing to catch a plane at the airport

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SUMMARY

The discussion centers on calculating the time it takes for a passenger to traverse a 110-meter moving sidewalk while walking at a speed of 3.0 km/h relative to the sidewalk, which itself moves at 1.5 km/h. The total speed of the passenger relative to the ground is 4.5 km/h (3.0 km/h + 1.5 km/h). To find the time taken to cover the distance, the formula time = distance/speed is applied, resulting in a time of approximately 26.67 seconds. Additionally, the distance walked by the passenger relative to the moving sidewalk is 110 meters.

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Michael B.
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could anyone help me with this problem and just explain how to find the answer? Thanks


A passenger rushing to catch a plane at the airport walks on a moving sidewalk at a speed of 3.0 km/h relative to the sidewalk in the direction that the sidewalk is moving. The sidewalk is 110 m long and moves with a steady velocity of 1.5 km/h. How long (in s) does it take for the passenger to get from one end of the sidewalk to the other, that i *to cover the 110 m?


Through what distance does the passenger walk relative to the moving sidewalk? This is the question I am having trouble with
 
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no in relation to the ground
 
It's a ratio between his walking speed on the sidewalk and off it in relation to the ground. The distance he walks is proportional to the speed he walks (for the same amount of steps). Understand?
 

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