Can unstable circuits with right-side poles exhibit resonant frequencies?

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SUMMARY

Active circuits with right-hand side poles in the imaginary-real plane can exhibit resonant frequencies, contrary to passive circuits which cannot. The output of such an unstable system can be described by the equation ke^{\alpha t}cos(ω_g t + φ), where ω_g represents the resonant frequency. While theoretically, the amplitude of oscillations can grow indefinitely, real circuits will encounter non-linearities that stabilize the amplitude, resulting in a distorted waveform with a fundamental frequency of ω_g.

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EvLer
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Can a circuit that has transfer function with poles in right-hand side part of the imaginary-real plane (unstable system) have resonant frequency?
 
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EvLer said:
Can a circuit that has transfer function with poles in right-hand side part of the imaginary-real plane (unstable system) have resonant frequency?
Sure. Several of my circuit designs had a resonant frequency that they kept wanting to find... :-)
 
EvLer said:
Can a circuit that has transfer function with poles in right-hand side part of the imaginary-real plane (unstable system) have resonant frequency?
No passive circuit can have poles in the RHP. An active circuit can have them and the output (assuming second order behavior) will be:
[tex]ke^{\alpha t}cos(\omega_g t + \phi)[/tex], where [tex]\omega_g[\tex] is the resonant frequency.<br /> Theoretically this circuit will produce oscillations in the frequency [tex]\omega_g[\tex] with amplitude growing to infinity.<br /> In a real circuit, when the amplitude grows, non linearities arise and the circuit will oscillate with fixed amplitude. Only we would not have a sinusoid anymore, but a distorted waveform, whose fundamental frequency is [tex]\omega_g[\tex] .<br /> <br /> I don´t understand why LaTex has not generated the correct image.[/tex][/tex][/tex]
 
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