Finding the Second Derivative of a Cubic Function

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SUMMARY

The discussion focuses on finding the second derivative of the cubic function y=(1-x^2)^3. The first derivative is correctly identified as -6x(1-x^2)^2. To find the second derivative, participants confirm the use of the product rule, defining u(x) as -6x and v(x) as (1-x^2)^2. This structured approach ensures accurate differentiation of the function.

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  • Knowledge of polynomial functions and their properties
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gr3g1
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Hey guys,

My function is : y=(1-x^2)^3
I found my first derivative as : -6x(1-x^2)^2
But i can't seem to find the second derivative.

Do I use the product rule?
 
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You are right use the product rule
[tex] f(x)=u(x)v(x)[/tex]
then
[tex] f'(x) = u'(x)v(x) + v'(x)u(x)[/tex]
here [itex]u(x)=-6x[/itex] and [itex]v(x)=(1-x^2)^2[/itex]
 
Last edited:
Thanks A lot
 

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