I got the formula, what does the angle effect? Net Magnetic force

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Homework Help Overview

The discussion revolves around a problem involving the net magnetic force on a bent wire situated in a uniform magnetic field. The wire's configuration includes an angle of 62° with the x-axis and carries a current of 2.0 A. Participants are exploring how the angle affects the calculation of the magnetic force using the relevant formula.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the role of the angle in the cross product related to magnetic force calculations. There are inquiries about how to apply the cross product with the angle, contrasting it with the dot product. Some participants also question the implications of opposing forces on the net force.

Discussion Status

The discussion is active, with participants seeking clarification on the mathematical concepts involved, particularly the application of the cross product. There is an exploration of different interpretations regarding the forces acting on the wire and their resultant effect.

Contextual Notes

Participants are working within the constraints of lecture notes and a specific problem setup, which may limit the information available for discussion. The nature of the problem suggests that assumptions about the forces and their directions are being examined.

mr_coffee
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Hello everyone, I think I am missing this problem because there is an angle invovled, but it doesn't seem to matter what angle it is from what my lecture notes say. but here's the question:
The bent wire shown in Fig. 28-39 lies in a uniform magnetic field. Each straight section is 2.1 long and makes an angle of = 62° with the x axis, and the wire carries a current of 2.0 A. What is the net magnetic force on the wire in unit-vector notation if the magnetic field is given by each of the following?
Here is the picture:
http://www.webassign.net/hrw/28-39.gif

Here is my work:
http://show.imagehosting.us/show/891660/0/nouser_891/T0_-1_891660.jpg
any ehelp would be great! :smile:

THe formula states: Fbtotal= F1 + F2 + F3 + ... + Fn then it says: F = I(L1 + L2 +...+Ln) x B
 
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Right, the angle comes in with the cross product at the end..
 
can you expland that explanation alittle more? How do you apply the cross product with the angle? I know the dot product has like AB = cos/|A||B| but i never heard of one for the cross product of A B.
 
The magnitude of [itex]\vec A \times \vec B[/itex] is [itex]AB \sin {\theta}[/itex].
 
Wouldn't both the forces be equal and just opposite in direction therefor the net force is zero??
 

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