Flywheel Rotation: Calculate Total Angle After 48.7s

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The discussion focuses on calculating the total angle of a flywheel after 48.7 seconds, starting from rest with a constant angular acceleration of 1.33 rad/s² for 23.5 seconds. The angular velocity at the end of the acceleration phase is calculated as 31.26 rad/s. The total angle through which the flywheel has turned is derived from both the acceleration phase and the constant velocity phase, with the angle during acceleration calculated as 1522.1 radians. The user seeks clarification on the correct calculation of the angle unwound during both phases.

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The flywheel of a steam engine begins to rotate from rest with a constant angular acceleration of 1.33 rad/s2. It accelerates for 23.5 s, then maintains a constant angular velocity. Calculate the total angle through which the wheel has turned 48.7 s after it begins rotating.
[tex]\omega = \omega _ o + \alpha t[/tex]
[tex]\omega = 0 + 1.33(23.5)[/tex]
[tex]\omega= 31.26[/tex]
[tex]31.26 = \Delta \theta / \Delta t[/tex]
Solving for [tex]\theta[/tex] gave me 1522.1 rad
which wasn't right.. can someone please help me?
 
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Find the angle unwound during its acceleration.
Find the angle unwound during the rest of the time while its at a constant rotation speed.

Add.
 
I'm stupid :-p
Thanks
 

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