Conservation of momentum and energy problem

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Homework Help Overview

The problem involves the conservation of momentum and energy in a scenario where a person fires a gun, leading to recoil. The participants are discussing the kinetic energy transferred to the person after the gun recoils, given specific masses and bullet velocity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the conservation of momentum and energy, questioning the assumptions made during the impact. Some have attempted to calculate recoil speed and set up equations based on momentum conservation, while others express confusion about the relationship between kinetic energy before and after the impact.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of energy conservation and momentum. Some guidance has been offered regarding the loss of energy during the impact, but no consensus has been reached on the final understanding of the problem.

Contextual Notes

Participants are working under the assumption that energy is conserved after the impact, but they acknowledge that this may not hold true during the impact itself. There is also a mention of energy loss that needs to be accounted for in the analysis.

cheez
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You forget to hold your gun against your shoulder and it recoils into you. How much Joules of kinetic energy end up in your shoulder? Assume you and the gun move together in the end.
masses: You=90 kg, gun=10kg, bullet= 0.0085kg
velocity of the bullet = 87m/s

I read the answer of it, but I don't get why the answer is that.
And the answer is

1/2 M gun x (M bullet * V bullet / M gun)^2
- 1/2 M gun+you x (M bullet * V bullet/ M gun+you) ^2thx!
 
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What have you tried?

After the impact, energy is conserved (you can't assume conservation during the impact though).
 
Päällikkö said:
What have you tried?

After the impact, energy is conserved (you can't assume conservation during the impact though).

Before I checked the answer, I calculated the recoil speed of the gun. And I set the equation using conservation of momentum to find the velocity of "you+gun".
i.e (M bullet * V bullet / M gun) * M gun = M you+gun V you+gun

But I don't know why the final answer is the Kinetic energy from the gun after the bullet is fired minus the Kinetic energy of "you+gun" after the impact.
 
By conservation of momentum, you have calculated the the momentum of the system directly after the after this inelastic impact. By looking at the kinetic energy before & after the collision you will notice that energy is lost somewhere; ask yourself where this energy has gone.

You also have to assume that no energy is lost during the time it take the rifle to you.

Regards,
Sam
 

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