Calculate the constant force exerted on the pole-vaulter

  • Thread starter Thread starter hshphyss
  • Start date Start date
  • Tags Tags
    Constant Force
Click For Summary

Homework Help Overview

The problem involves a pole-vaulter falling from a height and coming to rest on a foam-rubber pad. It requires calculating the velocity just before impact and the constant force exerted during the collision.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of kinematics to determine the velocity before impact and the use of impulse to find the force during the collision. There are questions about the correct approach and the necessary parameters for calculations.

Discussion Status

Some participants have provided guidance on using kinematic equations and the concept of impulse. There are differing interpretations of the initial conditions and calculations, with one participant suggesting a reevaluation of the time of fall.

Contextual Notes

There is a mention of confusion regarding the time of fall versus the stopping time, which affects the calculations. Participants are working within the constraints of the problem as posed, without additional information.

hshphyss
Messages
45
Reaction score
0
Can anyone help me with this problem? Thank-you

A 87 kg pole-vaulter falls from rest from a height of 6.8 m onto a foam-rubber pad. The pole-vaulter comes to rest 0.30 s after landing on the pad.
(a) Calculate the athlete's velocity just before reaching the pad ( in m/s downward).
(b) Calculate the constant force exerted on the pole-vaulter due to the collision (in N upward).

Would you incorporate kinematics in here or not? {x=1/2(vi+vf)t}
 
Physics news on Phys.org
Part (a) is a kinematics problem, so you're on the money there. The equation you mention will work just fine.

For part (b), think impulse.
 
For part a i got 6.8=1/2(0+vf)0.30 using kinematics and i got 45.33 m/s and i also tried -45.33 but neither worked. Did I do the work correctly?
 
I'm sorry, hshphyss. I lied. The equation you mentioned will work, but you need the time of fall. What you have is the stopping time.

Go back and refigure it as a free fall problem. How fast will something be falling if it starts from rest and falls a distance of 6.8 m? That's the kinematics problem that you solve for the first part. I'm getting 12 m/s.

After that, the time you have for it to stop plus the concept of impulse should give you the average force. I'm getting 3300 N. Remember that minus and plus signs here just indicate direction - and you already know the directions involved.
 
thank-you so much
 

Similar threads

Replies
3
Views
3K
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
6K
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
35
Views
11K