Particle in an infinite potential well

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Homework Help Overview

The discussion revolves around a quantum mechanics problem involving an electron in an infinite potential well, specifically focusing on energy transitions between quantum states when exposed to light. The participants explore the implications of photon energy and its relation to electron transitions within the well.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the energy levels of the electron and the conditions under which photons can be absorbed. They question the relationship between photon energy and the energy differences between quantum states, particularly regarding transitions to the n = 2 state.

Discussion Status

The conversation includes various interpretations of how energy absorption works in relation to quantum states. Some participants provide insights into the nature of off-resonant transitions and the concept of natural broadening, while others express confusion about the conditions necessary for photon absorption.

Contextual Notes

Participants are navigating the complexities of quantum mechanics, particularly the behavior of particles in potential wells and the implications of energy quantization. There is an acknowledgment of the limitations of the model being discussed, including the absence of intermediate energy levels in the infinite well scenario.

jdstokes
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Hi all,

I have an exam tomorrow and this problem concerns me greatly.

An electron is located in an infinitely deep one-dimensional square potential well. The width of the well is 1.00 nm.

(e) Light is shone on the electron causing it to jump from the ground state to the n = 3 state. What is the wavelength of the light?

(f) What would happen if light with wavelength twice that calculated in part f were shone on the electron in its ground state.

Answer to Question (f):
This does not correspond to a transition energy from the ground state to a higher energy state and so the photons will not be absorbed.

I'll work through the problem algebraically to show why I think the photon will in fact be absorbed.

The energy of the nth state is [itex]E_n = n^2E_1[/itex] where [itex]E_1 = \frac{h^2}{8mL^2}[/itex] is the energy of the ground state.

The transition energy between n = 3 and and the ground state is thus

[itex]\Delta E = E_3 - E_1 = 3^2E_1 - E_1 = 8E_1 = \frac{h^2}{mL^2}[/itex].

So the wavelength of the incident photon is

[itex]\lambda = \frac{hc}{\Delta E}[/itex].

If the light in part (f) has twice this wavelength, then the energy of the photons is half the value in part (e), ie

[itex]\Delta E' = 1/2\Delta E = 4E_1[/itex],

Since the transition energy between the ground state and the n = 2 state is just [itex]3E_1[/itex], why won't the electron be promoted to the n = 2 state?

Thanks.

James
 
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jdstokes said:
Since the transition energy between the ground state and the n = 2 state is just [itex]3E_1[/itex], why won't the electron be promoted to the n = 2 state?

Let's say it were. What happens to the remaining E1 of energy that was in the photon?
 
Maybe it is emitted in the form of another photon.
 
I don't understand this. If the energy difference ([itex]3E_1[/itex] say) has to precisely equal to the energy of the incident photon, what happens if the energy of the photon is arbitrarily close (but not equal) to [itex]3E_1[/itex]? How does nature decide whether or not to absorb the photon?
 
jdstokes said:
Maybe it is emitted in the form of another photon.

But there are no "intermediate" energy levels in the well that correspond to an energy difference of E1. There is no process to create the new photon.


I don't understand this. If the energy difference (LaTeX graphic is being generated. Reload this page in a moment. say) has to precisely equal to the energy of the incident photon, what happens if the energy of the photon is arbitrarily close (but not equal) to LaTeX graphic is being generated. Reload this page in a moment.? How does nature decide whether or not to absorb the photon?

In practice, absorption lines are not infinitely thin, as this analysis might suggest. For a single absorber, the dominant form of broadening comes from the fact that the states are not truly stationary (i.e. time-independent). You get a spread in energies from the energy-time uncertainty principle:

[tex]\Delta E \sim \frac{h}{\Delta t}[/tex]

This is called "Natural Broadening". Roughly speaking, any photon within that amount of the appropriate energy can be absorbed.
 
If you shine monochromatic light on an infinite square well system, even if the light is "off resonance" i.e. it's frequency doesn't match any of the transistion frequencies, then the light beam can still cause transitions from the ground state to the excited states. However, these transtions are off resonant in general and proceed at a greatly reduced rate. As the light beam is brought into resonance, the transition rate will spike (limited at the very least by the fact that the light beam isn't truly monochromatic). So in the simplest approximation nothing happens when the light is off resonant but what it really means is that very little happens compared to the case of resonant absorption. Look up the Rabi problem (the driven two level problem) for further clarification.

In my opinion, when using the photon concept, you can't look too deeply unless you are prepared to go all the way and use the full quantized theory.
 
Last edited:
Thanks for the clarification SpaceTiger and Physics Monkey :).
 

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