Ssec^3(w)dw is very easy but you need to pay atention

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SUMMARY

The integral Ssec^3(w)dw can be efficiently solved using integration by parts, which is the preferred method for many. However, an alternative approach involves rewriting sec^3(w) as 1/cos^3(w) and applying a substitution method with u = sin(w), leading to the integral ∫ du/(1-u^2)^2. While integration by parts is straightforward, utilizing partial fractions can deepen understanding, albeit requiring more effort. Careful consideration of the chosen method is crucial for effective problem-solving.

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  • Understanding of integration techniques, specifically integration by parts.
  • Familiarity with trigonometric identities, particularly secant and cosine functions.
  • Knowledge of substitution methods in integral calculus.
  • Experience with partial fraction decomposition in calculus.
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  • Study the method of integration by parts in detail, focusing on its applications.
  • Learn about trigonometric identities and their use in simplifying integrals.
  • Research substitution methods in integral calculus, particularly with trigonometric functions.
  • Explore partial fraction decomposition techniques and their applications in solving integrals.
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kallazans
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Ssec^3(w)dw
it is very easy if you use integration by parts, but you need to pay atention!

how about use a partial fraction ? if you like to have a hard work!

Someone agree with me?
 
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Actually, the way I would do that is to write sec3w as
1/cos3(w) and sec3(w)dw as
cos(w)dw/cos4(w)= cos dw/(1- sin2(w))2, make the substitution u= sin(w) so the integral becomes
∫ du/(1-u2)2 and THEN use partial fractions. Is that what you meant?
 


I agree that using integration by parts is a relatively easy way to solve this integral. However, I believe using partial fractions may also be a viable option. It may require more work, but it can also provide a deeper understanding of the problem. Ultimately, it's important to pay attention and carefully consider which method would be most efficient and effective in solving the integral.
 

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