Why Can't a Static Magnetic Field Do Work?

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Homework Help Overview

The discussion revolves around the question of why a static magnetic field cannot perform work on charged particles. Participants are exploring the relationship between magnetic forces, velocity, and work in the context of electromagnetism.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are examining the formula for the magnetic force on a charged particle and questioning how it relates to work. There is a focus on the implications of a static magnetic field and the conditions under which work is defined as zero.

Discussion Status

The discussion is active, with participants offering insights and questioning assumptions about acceleration and the nature of forces in magnetic fields. Some guidance has been provided regarding the relationship between force, velocity, and displacement, but no consensus has been reached.

Contextual Notes

Participants reference an exam question related to this topic, indicating that there may be specific constraints or expectations regarding the understanding of magnetic fields and work.

I done know
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Why can't a static magnetic field (not changing in time) ever do work? How do I express this formulaically? My only guess is that work is zero for a closed path.
 
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The force on a charged particle in a magnetic field is [tex]\vec{F} = q \vec{v} \times \vec{B}[/tex], right? Stare at that formula for a bit. Now ask yourself, how is the force related to the velocity? Then ask, how is work related to force?
 
I see, then dv/dt is 0 when the B field is static, so if a=0 then F=0 then W=0. Sound right?

Unfortunately this was on our last exam, and my answer was that W=qV and induced voltage is only a result of B flux changing in time.
 
Wait, how did you conclude that [tex]\frac{d\vec{v}}{dt} = 0[/tex]? The acceleration certainly isn't zero, there is a force acting.
 
Is it that the force is perpendicular to the magnetic field and work must be parallel to the displacement?
 
You are so close! The force is perpendicular to the field, but that's not what matters. What else is the force perpendicular to?
 
Ah, so because the force is perpendicular to the velocity, the force is perpendicular to the displacement.
 
Indeed. In simple terms, the power [tex]\vec{F} \cdot \vec{v}[/tex] is identically zero. Hence no work is done.
 

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