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-   -   Some new cookies started appearing in The Bakery very recently. (http://www.physicsforums.com/showthread.php?t=144193)

 Isolex Nov16-06 05:01 PM

Some new cookies started appearing in The Bakery very recently.

These cookies are in the shape of different letters of the alphabet. The Breadmaster started laying the cookies out to cool, and you observed the letters as he laid them out in this order:
H B N A I E P R O

What will be the next three letters he lays out to cool?

Can you solve my riddle?

 Isolex Nov16-06 09:43 PM

No one knows? Ha. I must be a genius.

 d_leet Nov16-06 10:30 PM

Quote:
 Quote by Isolex No one knows? Ha. I must be a genius.
It's only been 4 hours...

 Isolex Nov17-06 10:35 AM

 Jimmy Snyder Nov22-06 02:02 PM

Quote:
 Quote by Isolex These cookies are in the shape of different letters of the alphabet. The Breadmaster started laying the cookies out to cool, and you observed the letters as he laid them out in this order: H B N A I E P R O What will be the next three letters he lays out to cool?

Break the letters into three triplets and place the triplets one under the other as follows:
H B N
A I E
P R O

The first column is HAPPY, the second is BIRTHDAY, I assume that the third (NEO) are the first three letters of someone's name, but I can't figure out what it is. Is there a typo in the puzzle?

The next two letters are PT.

 Kurdt Nov23-06 03:18 PM

happy birthday neopets to be exact so presumably Isolex didn't in fact know the answer to last weeks lenny conundrum.

 Isolex Nov23-06 11:08 PM

I love how you jump to conclusions. I knew the answer was ptp before I posted it here. Just like I know this weeks' answer is 47. So back off. I just post them here because I like to see other people solve them. :grumpy:

 berkeman Nov23-06 11:41 PM

Quote:
 Quote by Isolex (Post 1169277) I love how you jump to conclusions. I knew the answer was ptp before I posted it here. Just like I know this weeks' answer is 47. So back off. I just post them here because I like to see other people solve them. :grumpy:
"Back off" is a bit aggressive. Welcome to the PF.

 Isolex Nov29-06 07:39 PM

You are confronted with the following formula:

A * [(B + C)(D - E) - F(G*H) ] / J = 10

Knowing that each variable is a unique, single-digit, nonzero number, and that C - B = 1, and H - G = 3, what is the number ABCDEFGHJ, where each letter is a digit? For example, if A = 4, B = 2, and C = 7, ABC would equal 427.

 Kurdt Nov30-06 08:34 AM

Quote:
 Quote by Isolex (Post 1174813) You are confronted with the following formula: A * [(B + C)(D - E) - F(G*H) ] / J = 10 Knowing that each variable is a unique, single-digit, nonzero number, and that C - B = 1, and H - G = 3, what is the number ABCDEFGHJ, where each letter is a digit? For example, if A = 4, B = 2, and C = 7, ABC would equal 427.
Seriously if you're going to insist on posting conundrums from another website at least wait until the competition on the other website is over because its unfair on other users of that website if they can find the answer somewhere else on the net.

 davee123 Nov30-06 01:26 PM

Quote:
 Quote by Kurdt (Post 1175222) Seriously if you're going to insist on posting conundrums from another website at least wait until the competition on the other website is over because its unfair on other users of that website if they can find the answer somewhere else on the net.
Looks like not only did he post it directly from another competition, but he failed to ask the correct question. The question asked here has 3 different answers. The *correct* question has only one answer. I wonder if he can answer his own question?

Want to give it a shot Isolex?

A, B, C, D, E, F, G, H, and J are digits in the range 1-9.
C - B = 1
H - G = 3
A * ((B + C)*(D - E) - F*(G*H)) / J = 10
What are the 3 possible values of ABCDEFGHJ?

For those interested, a CORRECT re-statement of the problem is:

A, B, C, D, E, F, G, H, and J are digits in the range 1-9.
C - B = 1
H - G = 3
A * ((B + C)^(D - E) - F^(G*H)) / J = 10
What is the value of ABCDEFGHJ?

DaveE

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