How to Slice a Donut into 13 Pieces with Only Three Cuts

  • Context: High School 
  • Thread starter Thread starter terrabyte
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Discussion Overview

The discussion revolves around the problem of determining the maximum number of pieces a standard toroidal doughnut can be sliced into using a specified number of cuts. Participants explore various cutting strategies and configurations, with a focus on the implications of rearranging the doughnut between cuts and the use of planar cuts.

Discussion Character

  • Exploratory
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants suggest that with two cuts, a maximum of 5 or 6 pieces can be achieved, depending on the cutting technique used.
  • One participant describes making an X-shaped cut to achieve 6 pieces, while another proposes a method involving rearranging the doughnut to also reach 6 pieces.
  • There is a proposal that with three cuts, it may be possible to achieve up to 13 pieces, although this claim is met with skepticism from others who suggest a maximum of 8 pieces.
  • A participant describes a method involving three cuts that results in 12 pieces, indicating that reaching 13 pieces is plausible but not clearly demonstrated.
  • Some participants express a desire for visual aids, such as drawings, to better illustrate their cutting strategies.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the maximum number of pieces achievable with two or three cuts, with multiple competing views and methods presented throughout the discussion.

Contextual Notes

Some claims depend on the interpretation of rearranging the doughnut between cuts, and there are unresolved mathematical steps in the proposed cutting strategies.

terrabyte
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One Doughnut
Two Cuts

what's the maximum number of pieces you can get?

and no crazy stuff like "i bought 12 doughnuts and i cut them with my baseball bat and some had like 35 pieces!"

PS> the pieces don't have to be the same size, and the doughnut is standard ring (toroid) shaped
 
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any folding allowed?
 
terrabyte said:
One Doughnut
Two Cuts

what's the maximum number of pieces you can get?

and no crazy stuff like "i bought 12 doughnuts and i cut them with my baseball bat and some had like 35 pieces!"

PS> the pieces don't have to be the same size, and the doughnut is standard ring (toroid) shaped

And the cuts need to be planar !
 
yes planar cuts please

don't fold the doughnuts! Bad!
 
I get 5 , but surely you can make more, right ?

EDIT : I rearranged before the second cut.

PS : Hey, I just green lights appear - neat ! Have they always been around ?





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Last edited:
yeh the lights have always been around.

explain how you got 5 :D

wish we had a chalkboard. this type of problem is way more fun with something to draw with
 
terrabyte said:
yeh the lights have always been around.

explain how you got 5 :D

wish we had a chalkboard. this type of problem is way more fun with something to draw with

I drew a picture, but my posting rules say that I may not post attachments...WHY ?
 
I got 6. (and ruined a perfectly good bagel).
The only way I can explain it is if you look at it edge on, I made an X shaped cut.(which also you would see if you turned it around and look at the other side).
 
Math Is Hard said:
I got 6. (and ruined a perfectly good bagel).
The only way I can explain it is if you look at it edge on, I made an X shaped cut.(which also you would see if you turned it around and look at the other side).

Looks like the winner !
 
  • #10
wheee! what do I win? A donut?
actually, I'm expecting Terrabyte to write back any second and post a solution showing how 24 pieces can be made from two strategic cuts... :biggrin:
 
  • #11
You can also get 6 pieces by rearranging between the cuts. Put the donut flat on the table and make a downwards cut through the center.

That gives you two C shapes. Align one on top of the other and make another downward cut, slicing off the 'prongs'. So you get 4 prong pieces plus 2 attenuated C shapes.

Obligatory follow-up question. Same rules, but three cuts allowed now. :smile:
 
  • #12
Damn, I was using a jelly donut! Not only did it restrict how many pieces I could get, it made a real mess.

Njorl
 
  • #13
ceptimus said:
You can also get 6 pieces by rearranging between the cuts. Put the donut flat on the table and make a downwards cut through the center.

That gives you two C shapes. Align one on top of the other and make another downward cut, slicing off the 'prongs'. So you get 4 prong pieces plus 2 attenuated C shapes.

Obligatory follow-up question. Same rules, but three cuts allowed now. :smile:

This seems pretty easy considering the other posts: 18.
 
  • #14
yeh, i came up with 6 pieces using the "X" cut as well, but the "C" cuts was a nice surprise. Good thinking!

Next Question: you have one Labrador Retriever... :surprise:
 
  • #15
If no rearranging is allowed between cuts, I think the maximum with three cuts is thirteen pieces.
 
  • #16
How did you get 13? I get 8...
 
  • #17
Learning Curve said:
How did you get 13? I get 8...

I'll show you how to get more than 8:

Three cuts:
If you view the donut from the side, the first cut is from the top left of the hole to the bottom right.
The second cut is from the top right to the bottom left.
There should now be six pileces - four wedges, and two C's.

The third cut is vertical, and slightly off center. It cuts through one of the C's twice, and through all for wedges. That makes for 12 pieces. (Sorry no illustrations.) It's not that hard to get to 13 from there.
 

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