Finding Critical Point of f(x) with f(0) = 0

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Discussion Overview

The discussion revolves around finding the critical point of the function f(x) = sin(1/x)*x^2 for x not equal to 0, with f(0) defined as 0. Participants explore the implications of this critical point, particularly whether it is a local minimum, maximum, or inflection point, and how to demonstrate these properties through derivatives.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant differentiates f(x) and finds f' = -cos(1/x) + 2xsin(1/x), questioning how to find critical points, particularly at x=0.
  • Another participant points out that the derivative found does not include the point x=0 and suggests using the definition of the derivative to find f'(0).
  • There is a discussion about showing that x=0 is not a local minimum, maximum, or inflection point, with one participant suggesting the use of the second derivative and noting its discontinuity at x=0.
  • A participant proposes using the definition of a local maximum to demonstrate that f(0) is not a local maximum or minimum.
  • Further parts of the original question involve analyzing the function g(x) = 2x^2 + f(x) and showing that it has a global minimum at x=0 while its derivative changes sign infinitely often in both directions around 0.
  • Another part involves the function h(x) = x + 2f(x), where participants discuss showing that h'(0) > 0 but that h is not monotone increasing on any interval including 0.
  • One participant suggests showing that g(x) is greater than or equal to x^2 for all x as a potential way to demonstrate that x=0 is a global minimum.

Areas of Agreement / Disagreement

Participants generally agree on the need to analyze the derivatives to understand the behavior of the functions at the critical point, but multiple approaches and interpretations exist regarding how to demonstrate the properties of these functions, particularly concerning local extrema and monotonicity.

Contextual Notes

There are unresolved aspects regarding the continuity and differentiability of the functions involved, particularly at x=0, which affects the analysis of local extrema and monotonicity.

cateater2000
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let f(x)=sin(1/x)*x^2 for x not 0, and f(0)=0. show that x=0 is a critical point for f which is neither a local minimum, a local maximum, nor an inflection point.

well I tried differentiating this, and got f'=-cos(1/x) +2xsin(1/x). to find a critical point i make f'=0. Not sure how to do this. Do I take the limx->0?

Any hints or tips would be great
 
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What you've done here, is to find the derivative of f at all points EXCEPT at x=0!
But you are to find f'(0)...
Use the definition of the derivative.
 
k thanks i'll try that
 
If you're a bit unsure what I mean, the definition of f'(0) is:
[tex]f'(0)=\lim_{h\to{0}}\frac{f(0+h)-f(0)}{h}[/tex]
 
yeh i got that to work, now how do I show that it's not a local min,max or inflection. Would I look at the second derivative? If that's not defined it's not anything?
 
cateater2000 said:
yeh i got that to work, now how do I show that it's not a local min,max or inflection. Would I look at the second derivative? If that's not defined it's not anything?
The standard second-derivative fails, since the first derivative is discontinuous at x=0 (the 2.derivative is not defined).

It remains to be shown that f(0) is not a local maximum/minimum.
This should be fairly easy to show..

Use, for example, the following definition of local maximum:
We say that a function f has a local maximum at [tex]x_{0}[/tex], iff there exists a [tex]\delta>0[/tex] so that for all [tex]x\in{D}(x_{0},\delta),f(x)\leq{f}(x_{0})[/tex]
I've assumed that the x's in the open [tex]\delta[/tex]-disk are in the domain of f, as is the case in your problem.

Note that this definition makes no assumption of differentiability or continuity of f.
 
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ok i finished that part of the question.( this is a 4 part question)

I can't figure out these 2 parts. Any tips would be fantastic
f(x)=x^2*sin(1/x)
1.let g(x)=2x^2 +f(x) (f from the first question i asked)

Show g has a global minimum at x=0 but g'(x) changes sign infinitely often on both (0,e) and (-e,0) for any e>0.

For this question I can easily show 0 is a critical point. But when I show it's a minimum is what's difficult, when I differentiate twice I cannot see that f''(0)>0


2. Let h(x)=x+2f(x). Show h'(0)>0, but h is not monotone increasing on any interval that includes 0.

I know how to show h'(0)>0 but have no idea how to show it's monotone increasing.



Again any help would be fantastic
thanks in advance
 
Show that for 1., g(x)>=x^2 for ALL x.
How can that help you in showing that x=0 must be a global minimum?
 

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