Calculating Wavelength without distance

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Homework Help Overview

The discussion revolves around calculating the wavelength of light given its frequency, specifically for a frequency of 5.58×1014 Hz. The subject area is optics within the broader field of physics.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to understand how to find the wavelength without having distance information. Some participants clarify the relationship between speed, frequency, and wavelength, while others emphasize the need for the speed of light in the calculation.

Discussion Status

Participants are exploring the formula relating speed, frequency, and wavelength. There is an ongoing clarification of how the formula can be rearranged to solve for wavelength, with some guidance provided on the necessary constants involved.

Contextual Notes

The original poster identifies as a first-year physics student, indicating a need for foundational explanations. There is also a mention of the challenge posed by the requirement to find wavelength without distance, which may suggest a misunderstanding of the relationship between these quantities.

StotleD
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A question has been given to me: what is the wavelength for light with a frequency of 5.58×1014 Hz? How do you find the wavelength without the distance?
 
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You can use the equation [itex]c = f\lambda[/itex], where c is the speed of light (in free space).
 
That formula includes the wavelength which is what I am trying to solve for. I am a first year physics student so you'll have to take it easy.
 
Well if it didn't include the wavelength you couldn't solve for it, could you?

c= λf so λ= c/f.

You are given the frequency, f, and you know, or can look up, the speed of light, c.
 

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