Calculating Tension in a Rope: A 2kg Stone and 1m Radius

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SUMMARY

The discussion focuses on calculating the tension in a rope attached to a 2 kg stone moving in a circular path with a radius of 1 meter and a velocity of 4 m/s. The tension at the top of the circle is calculated as 12.4 N, while the tension at the bottom of the circle is determined to be 51.6 N. The calculations utilize the formulas for centripetal force (Fc = mv²/r) and gravitational force (Fg = mg) to derive the tension in the rope (Ft). Both solutions provided by participants are confirmed to be correct.

PREREQUISITES
  • Understanding of centripetal force (Fc) and gravitational force (Fg)
  • Familiarity with Newton's second law of motion
  • Basic knowledge of circular motion dynamics
  • Ability to perform algebraic calculations involving forces
NEXT STEPS
  • Study the effects of varying mass and radius on tension in circular motion
  • Explore the relationship between velocity and centripetal force in different scenarios
  • Learn about the role of tension in various physical systems, such as pendulums
  • Investigate real-world applications of circular motion principles in engineering
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of circular motion and tension in ropes or cables.

Atilla1982
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A stone with mass 2,0kg is tied to a rope with radius 1 meter to the circle center, and has the velocity 4 m/s.

a) What's the tension on the rope on the top point of the circle?

b) What's the tension on the rope on the bottom point of the circle?


Here's my attempt to solve these.

a) Fc = mv^2/r Fg= mg Ft= the force applied on the rope

Fc=Ft + Fg
Ft=Fc - Fg
Ft=mv^2/r - mg
Ft=2*4^2/1 - 2*9,8
Ft=12,4 N

b)
Fc=Ft - Fg
Ft=Fc + Fg
Ft=mv^2/r + mg
Ft=2*4^2/1 + 2*9,8
Ft=51,6 N

Can anyone please verify that this is correct?
 
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Both of your solutions are correct.
 

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