How to get mag. & angles of resultant couple moment

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SUMMARY

The discussion focuses on calculating the magnitude and direction of the resultant couple moment from two valve handles. The user has calculated moments MA and MB as 6.125 Nm and 4.375 Nm, respectively, using the formula M=(d)(F). The key challenge is determining the direction of these moments, which are vector quantities. The user is advised to apply the cross product formula (\vec{M} = \vec{r} \times \vec{F}) to find the resultant vector's direction.

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caddyguy109
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I have another thread for another problem, but no one seems to be responding about this second problem, so i'll post it here.

Need to find the magnitude and direction/space angles of the resultant couple moment of two valve handles being turned, as pictured:
http://img347.imageshack.us/img347/2488/problem64sx.jpg

Would the resultant mean at the origin of the axes? So far, I've done this, using the left as A and the right as B:

M=(d)(F)
MA=(0.175m)(35N)=6.125Nm
MB=(0.175m)(25N)=4.375Nm

Should the forces have unit vectors k on them? If what I did is somewhat right, then how do I get the resultant magnitude and direction if the only other piece of data given is that the wheel on the right is angled 60deg. from the y-axis--no other distances, etc?
 
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Your magnitudes are correct, but these moments are vectors. What direction do they point? ([itex]\vec{M} = \vec{r} \times \vec{F}[/itex]) Add those vectors.

(And please don't post the same question in mutliple threads! It's generally best to post one problem per thread.)
 

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