Final speed and compression in a kinetic-potential energy problem?

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Homework Help Overview

The discussion revolves around a kinetic-potential energy problem involving a package released on an incline, interacting with a spring. Participants are exploring the calculations related to the speed of the package before it reaches the spring, the maximum compression of the spring, and the rebound distance of the package.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss breaking down forces into components and applying energy conservation principles. There are attempts to calculate final velocity and spring compression using equations involving kinetic and potential energy, but some results are noted as incorrect. Questions arise about the work done against friction and the conditions at maximum spring compression.

Discussion Status

Some participants have provided calculations and expressed uncertainty about their results. There is acknowledgment of potential errors in calculations, particularly regarding the work done against friction. Others have indicated that they arrived at correct answers after reassessing their work.

Contextual Notes

Participants are operating under the constraints of homework rules, which may limit the sharing of complete solutions. There is an emphasis on understanding the energy methods used and the implications of friction in the problem setup.

erik-the-red
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A 2.00-kg package is released on a [tex]53.1 ^\circ[/tex] incline, 4.00 m from a long spring with force constant 120 N/m that is attached at the bottom of the incline. The coefficients of friction between the package and the incline are[tex]\mu_{s} \;=\; 0.40[/tex] and [tex]\mu_{k} \;=\; 0.20.[/tex] The mass of the spring is negligible.

1. What is the speed of the package just before it reaches the spring?

2. What is the maximum compression of the spring?

3. The package rebounds back up the incline. How close does it get to its initial position?
 

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I forgot that I violated the sticky rule. Sorry!

I started off by breaking the force of weight into x and y components. I used the equation [tex]K_1+U_1+W_f=K_2+U_2[/tex]. But, [tex]U_1=K_1=0[/tex]. I'm looking for the final velocity, which can be found in the final kinetic energy.

My answer was 8.50 m / s, but that was incorrect.

For the second problem, I used [tex]K\Delta X=f_k+mgsin(\Theta)[/tex]. Solving for [tex]\Delta X[/tex], I got .151 m, which is also incorrect.

I don't know how to do part C.
 
erik-the-red said:
I started off by breaking the force of weight into x and y components. I used the equation [tex]K_1+U_1+W_f=K_2+U_2[/tex]. But, [tex]U_1=K_1=0[/tex]. I'm looking for the final velocity, which can be found in the final kinetic energy.

My answer was 8.50 m / s, but that was incorrect.
The idea of using energy methods is fine. Show exactly what you did.

For the second problem, I used [tex]K\Delta X=f_k+mgsin(\Theta)[/tex]. Solving for [tex]\Delta X[/tex], I got .151 m, which is also incorrect.
When the spring is maximally compressed the force on the package will not be zero. Once again, use energy methods.
 
For part a, I did [tex]K_2+U_2=W_f[/tex].

So, [tex](1/2)(2.00)(v_2)^2 + (2.00)(9.80)(-3.20) = -.47[/tex]

[tex]v_2=7.89[/tex] m/s.

But, that is also not correct.
 
Show how you calculated the work done against friction.
 
Yeah, something was SERIOUSLY not right with that work done by friction.

I ended up getting the correct answer. I must have punched in something wrong in my calculator.

Thanks!
 

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