Solving the Antiderivative of sqrt(1-(x^2/2))

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Homework Help Overview

The discussion revolves around computing the antiderivative of the function \(\sqrt{1-\frac{x^2}{2}}\). Participants are exploring methods and transformations related to integration techniques.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants suggest using a trigonometric substitution, specifically \(x=\sqrt{2} \sin u\), to approach the integral. Others mention the potential connection of the integrand to inverse hyperbolic functions and question whether it can be expressed in terms of elementary functions.

Discussion Status

The discussion is active, with various approaches being proposed. Some participants express uncertainty about the algebraic expressibility of the integral, while others provide insights and transformations that may lead to further exploration.

Contextual Notes

There is a mention of the limitations of expressing the integral in terms of elementary functions, as well as the use of computational tools like Mathematica to assist in evaluation.

Icebreaker
[SOLVED] Simple Antiderivative

How would I compute the antiderivative of

[tex]\int \sqrt{1-\frac{x^2}{2}}[/tex]

It looks familiar, but I can't quite remember how...
 
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Put

[tex]x=\sqrt{2} \sin u[/tex]

and go from there.
 
U can also put the Riemann measure on [itex]\mathbb{R}[/itex] : [itex]dx[/itex]. :wink:

Daniel.
 
Ah yes, of course. Thanks.

Quick follow-up:

[tex]\int\log|\sqrt{1-x^2}+x|[/tex]
 
Last edited by a moderator:
I think that integrand is related to an inverse hyperbolic trig function... but I'd have to play around with it to work out which one. Maybe somebody else...
 
Perhaps it simply cannot be expressed algebraically?
 
Icebreaker said:
Perhaps it simply cannot be expressed algebraically?
It cannot be expressed in terms of elementary functions, you are correct.

I love Mathematica :smile:

Alex
 

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