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 P: 134 Does l'hospitals rule work here?: $$\lim_{h\to_0}\frac{f\left(8+h\right)-f\left(8\right)}{h}$$ for $$f\left(x\right)=x^\frac{4}{3}$$ then i would get, $$\lim_{h\to_0}\frac{f\left(8+h\right)}{1}$$ then, $$=\frac{\left(8\right)^\frac{4}{3}}{1}$$ ? is that it?...