So this is the same thing i did before but updated with the new signs
B)
I_x=.2(8.485289.02723)= .10839
I_y=.2(8.48528(11.9795))= 4.092996
and to solve for the F_average i just do divide by .05
so
F_x=.10839/.05 = 2.1678 N
F_y=4.092996/.05 = 81.8591 N
