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So this is the same thing i did before but updated with the new signs
B)
I_x=.2(8.48528-9.02723)= -.10839
I_y=.2(8.48528-(-11.9795))= 4.092996
and to solve for the F_average i just do divide by .05
so
F_x=-.10839/.05 = -2.1678 N
F_y=4.092996/.05 = 81.8591 N
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