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franznietzsche
#3
Feb8-04, 11:53 PM
P: 1,783
Thank you.

Originally posted by lethe
this is correct. you only need the Christoffel symbols if you are taking a derivative.
i know, but that transofrm is the same as the one for the christoffel symbols except the christoffel symbol's transformation rule has the added term:
[tex]
\frac{\partial x^i}{\partial x^k}\frac{\partial^2 \bar x^m}{\partial x^j \partial x^k}
[/tex]

That is what i was referring to.