 Quote by konichiwa3x
[tex]$ 15 = (distance \quad between \quad humps)/T [/tex]
where T is the time period of oscillation.
[tex]$ T = 2\pi/\omega= 2\pi \sqrt{\frac{m}{k}} [/tex]
where 'm' is the mass of the man? (or is it the mass of man+car) Please explain.
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Hi konichiwa3x!
Sorry to take so long.
ok … you know the actual formula, so you don't need the quadratic equation … that saves time!
If your calculation of the spring constant is correct (and you haven't shown us, so I can't check it), then you
must use the mass of man+car, because that's what the suspension is having to put up with!
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And what about the first part of the question regarding the graphs?
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"sketch graph" means that you don't need to put in any values … the examiner only wants to see the rough
shape of the graph (eg, is it a line, a parabola, a sine curve, a V-shape, …).
So just say in words what the shape is … and then draw it!
To start you off … in words, what happens to the height of the car if there is
no suspension (ie suspension not functioning)?